25a^2=14-25a

Solution for 25a^2=14-25a equation:

25a^2=14-25a

We move all terms to the left:

25a^2-(14-25a)=0

We add all the numbers together, and all the variables

25a^2-(-25a+14)=0

We get rid of parentheses

25a^2+25a-14=0

a = 25; b = 25; c = -14;
Δ = b2-4ac
Δ = 252-4·25·(-14)
Δ = 2025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2025}=45$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-45}{2*25}=\frac{-70}{50}
=-1+2/5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+45}{2*25}=\frac{20}{50}
=2/5
$